AC Phasor and Sinusoid

A compact view of how a rotating AC phasor maps to instantaneous sinusoidal voltage.

theta / v(t)
angle42deg
instant v(t)+0.67Vm
amplitude1.00Vm
relationv = Vm sin theta
Rotating phasor to sinusoidtheta / v(t)
ReImv(t)time+Vm-Vmtheta = 42 deg0 deg360 deg — phasor rotation, not the wave axistheta = omega tv(t) = Vm sin theta
speed
Control visualization - the phasor rotates automatically; pause, change speed, or scrub the phase to see the sinusoid projection.

Download the AC Phasor and Sinusoid diagram

AC phasor diagram for BESS: rotating phasor on Im/Re complex plane at 183 deg mapped to v(t)=Vm sin theta waveform
An interactive AC phasor diagram maps a rotating vector on the complex plane to instantaneous sinusoidal voltage v(t)=Vm sin theta, showing how angle and amplitude drive AC waveforms.

Free to download and reuse — including commercially — under CC BY 4.0, with credit to BESS.engineer. Licence & attribution →
Browse all BESS diagrams →

Download diagram

What it shows

A phasor is a rotating vector of fixed length (the amplitude Vm) spinning at the system frequency. Its vertical projection at any instant equals the instantaneous voltage, v(t) = Vm·sin(θ). As the phasor sweeps from 0° to 360°, the diagram traces out one full cycle of the AC sinusoid — the rotating picture and the time-domain wave are the same information in two views.

Why it matters for BESS

Inverters, transformers, and grid studies all reason about AC quantities as phasors. Holding amplitude and phase in your head as a single rotating vector is what makes power-factor, reactive-power, and ride-through analysis tractable — every other electrical visual in this library builds on this projection.

Frequently asked

What is a phasor?
A phasor is a complex number (magnitude and angle) that represents a sinusoidal quantity of known frequency. The magnitude is the waveform amplitude and the angle is its phase; rotating it and reading the vertical projection reconstructs the instantaneous value.
Why use phasors instead of time-domain waveforms?
At a single steady-state frequency, phasors turn differential equations into algebra. Adding two AC signals becomes vector addition, and phase relationships (leading/lagging) are read directly as angles.
Is the phasor magnitude here the peak amplitude or the RMS value?
Here it is the peak amplitude Vm: the phasor is drawn at full length so its vertical projection reads directly as the instantaneous voltage v(t) = Vm·sin(θ). Engineering practice and the IEEE C37.118 synchrophasor standard instead scale the magnitude to RMS, Vm/√2, so a synchrophasor is written X = (Vm/√2)·e^jφ. RMS is the convention used for power: with RMS magnitudes, complex power S = V·I* returns watts and VArs directly, with no leftover factor of ½. It is the same vector at the same angle — only the magnitude convention differs.

References

Standards and authoritative sources this visual is built on:

  1. IEC/IEEE 60255-118-1:2018 — Measuring relays and protection equipment — Part 118-1: Synchrophasor for power systems — Measurements (formal definition of the phasor representation of a sinusoid) — IEC / IEEE, 2018
  2. IEEE Std 1459-2025 — IEEE Standard Definitions for the Measurement of Electric Power Quantities Under Sinusoidal, Nonsinusoidal, Balanced, or Unbalanced Conditions — IEEE, 2025
  3. IEC 80000-6:2022 — Quantities and units — Part 6: Electromagnetism (defines instantaneous value, angular frequency, phase, and phasor quantities) — IEC, 2022

← Explore all BESS visuals